LESSONS OF EASTER ISLAND
March 17th, 2016
LOW RPM PERMANENT MAGNET DC GENERATOR
STOCK N0.443541
Two highenergy saturated C8 ceramic magnets.
Stainless steel 12.7mm (1/2in) diameter, 40mm length, with 1mm fulllength flat.
16slot armature 52mm diameter wound with AWG25 magnet wire (fusing current 24 amps) Extralong 8x14mm brush assemblies including spring, pigtail and cap – stock no. 443732 Two doublesealed 32mm OD ball bearings – replacement stock no. 17111.
Either direction – The red output wire is positive for clockwise rotation from the shaft end. Zero to 5,000 rpm (84Hertz), generates at all speeds.
Four M6 tapped holes on the front or rear end caps, or by hose clamps on the magnet drum. 4.5Kg (9.8lb). Shipping weight 4.6Kg (101b), dimensions 150x150x300mm (6 x 6 x 12in). Internal resistance 7.7 ohms. Inductance 16 mH.
Se...
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33 ихх 
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Figure N.6: a) Exploded % view of receiver/boiler. b) % view of assembled
receiver/boiler.

Figure N.8: Main body of the receiver/boiler. 
Figure N.9: Assembled receiver/boiler being heated on electric burner for initial mixing of the draw salt thermal bath. 



Figure N.12: Receiver/boiler being submitted to concentrated solar insolation. 
IMPULSE STEAM TURBINE
AND
GEAR TRAIN
Figure M.2: Detailed drawing of T500 impulse steam turbine rotor (blades) ,
housing, and nozzle design.




і –
Figure M.4: Detailed drawing of bearing plate three, low speed gear housing, and
intermediate speed gear housing.
APPENDIX N
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Rankine Cycle Calculations k := 103 
v2a: 
Boiler Inlet (actual) P2p := 963.17cPa 
0.5144kJ— kgK 
s2p : 
v2p : 
Turbine Exit (actual — for using turbine inlet values)
kJ kJ
P4p t := 101.323cPa h4p t := 2679.7689— s4p t := 7.3655 v4p t :
4P_t 4P_t kg 4pt kgK 4pt
Turbine Exit (ideal — for using turbine inlet values)
kJ kJ
P4 t := 101.325:Pa h4 t := 2496.9084 s4 t := 6.8754
– 4_t kg 4t kgK
Turbine Exit (theoretical / actual — for using boiler exit values and dT)
P4p_b := 101.323cPa h4p_b := 3105.0094^ s4p_b := 8.263^^ v4p_b
Turbine Exit (theoretical / ideal — for using boiler exit values and dT)
wturbine_out_actual • h3t h4p_t 
kJ wturbine... 
Steam Turbine Calculations
k := 103
Mass Flow Rate into the turbine: := 4.87310 3 —
kj kJ
Enthalpy Values for Turbine Inlet (h3) and Outlet (h4): h3 := 2764 0848— h4 := 2679 7689—
3 kg 4 kg
Heat Transfer from the Turbine: Qdot := mdot (h4 – h3)
Qdot = 410.871W
Pinlet := 480.537cPa Poutlet := 101.325oPa
Tinlet := 4314Ж
mdo^ p in’Vinlet’ Anozzle mdot = p out’ Vout’ Anozzle
Zinlet • 10in Zoutlet • 6in
From the Steam Tables:
hinlet • h3 houtlet • h4
Power Output of the Turbine
Work Output of the Turbine is solved by:
To determine the efficiency of the turbine (or any machine in that matter), we compare the actual performacne of the machine under given conditions to the performance that would have been achieved in an ideal process...
Read MoreMass Flow Rate through Steam Turbine Nozzle
Area of the Steam Turbine Nozzle
Pt := 0.480537MPa
From the Steam Tables for the given pressure and temperature
Since the inlet temperature is higher than the saturation temperature, the steam is superheated.
Speed of Sound








P
exit
Pexit := 101.325Pa
Mach Number
(assuming M=1 because of geometry)
V
M := 1 M
a
The velocity of the flow is:
3 m
V := Ma V = 1.03 x 10
ЛАЛ/
s
The mass flow rate is thus:






Boiler Efficiency k := 103
Direct Method
Directly defined by the exploitable heat output from the boiler and bythe fuel power input of the boiler.
Qoutput
n boiler_direct “ “Q
Qinput
Indirect Method
Determines efficiency by the sum of the major losses and by the fuel power of the boiler. The indirect method provides a better understanding of the individual losses on the boiler efficiency.
Qlosses
n boiler_indirect “ 1 Q
Qinput
Qinput := 11072kW Qoutput := 1kW
Qoutput
n boiler_direct := ~Q
Qinput
n boiler_direct 9032%
Qlosses
n boiler_indirect := 1 Q
Qinput
n boiler_indirect 96845%
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